If current of 0.2 Apms is passed through copper(ll) sulphate for tow hours, how much copper do you get?
- Write out the half equation
- Work out coulombs of electrons flowing
Q= IT
time is 2x60x60 (times 60 makes minutes, times 60 again makes it seconds)
Q= 0.2 x 7200= 1440 coulombs
- Convert C into moles of electrons
Mol= 1440/96500
Mol= 0.015
- Work out scale factor
For every 2 moles of electrons, there will be one Cu
Sf= Moles of product/ moles of electrons
Sf= 1/2
Sf= a half
- Work out moles of product using Scale factor
0.015x1/2= 0.0075 Moles of Cu
- Convert moles into mass
0.0075 x 63.5= 0.48g of copper