At the positive electrode, electrons will be lost: to show this we write the lost electrons as products:
2Br- > Br2 + 2e-
Make sure the charges are equal on both sides: 1- > 1-.
At the negative electrode, electrons will be gained so we write them as reactants:
2H+ + 2e- > H2
And to make sure the charges are the same on both sides: 0 > 0.
Hi, just a very small point, I think the equation at the anode should be 2Br- ---> 2Br + 2e- :) Thanks for all the notes btw, they're really really helpful!!! :)
ReplyDeleteAh, yeah, thank you! Have changed that!
DeleteIt's ok :)
I think you might have been right the first time, I use BrINClHOF to determine if the element is found naturally in pairs and Bromine is one of them, this could mean Br2 was right? Obviously I am just trying to make this already brilliant revision checklist better for everyone, rather than starting a meaningless argument.
DeleteOh yes you are right Fellow Saturn... I guesse I will change it back again hahaha, probably end up changing it a third time ;)
DeleteThanks for the help!
Oh wait, I think its because it makes it look like one bromine with a negative charge of two, not sure how its meant to be written so I will just leave it like that but if anyone is confused they can just have a nice little read of this haha
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ReplyDeleteThanks sooo much for this blog it is the best revision source ever!!!! (now my school recommend it)
ReplyDeleteHope your exams go really well for you!!
Hahaha that's a big compliment, thank you :) Oh that's cool, give everyone best wishes for results day!
DeleteSo do I! Haha, and you too :)
Hannah can I ask what you got in IGCSE bio, chem and phys?
ReplyDeleteI'm sure it was 3 A*s well at least I think you deserve it!
yup she said she got 3 A*'s in each science (bio, chem & phys)
DeleteHannah can I ask what you got in IGCSE bio, chem and phys?
ReplyDeleteI'm sure it was 3 A*s well at least I think you deserve it!
can we have the other half equations for the other compounds
ReplyDelete