1.57 calculate the amounts of the products of the electrolysis of molten salts and aqueous solutions

One faraday is 96500 coulombs. It is also one mole of electrons.

If current of 0.2 Apms is passed through copper(ll) sulphate for tow hours, how much copper do you get?

• Write out the half equation

Cu2+ + 2e > Cu

• Work out coulombs of electrons flowing

Coulombs= current x time
Q= IT

time is 2x60x60 (times 60 makes minutes, times 60 again makes it seconds)

Q= 0.2 x 7200= 1440 coulombs

• Convert C into moles of electrons

Moles= C/Faraday

Mol= 1440/96500

Mol= 0.015

• Work out scale factor

Cu2+ + 2e > Cu

For every 2 moles of electrons, there will be one Cu

Sf= Moles of product/ moles of electrons

Sf= 1/2

Sf= a half

• Work out moles of product using Scale factor

so we do the moles of electrons times the scale factor

0.015x1/2= 0.0075 Moles of Cu

• Convert moles into mass

Moles x Mr

0.0075 x 63.5= 0.48g of copper