This blog will cover and explain the specification for Edexcel triple science course 2013 Chemistry. Hope it helps :)
Showing posts with label Electrolysis. Show all posts
Showing posts with label Electrolysis. Show all posts
Wednesday, 1 May 2013
1.56 recall that one faraday represents one mole of electrons
One Faraday is 96500 coulombs. That is the amount of coulombs in one mole of electrons.
Tuesday, 30 April 2013
1.57 calculate the amounts of the products of the electrolysis of molten salts and aqueous solutions
One faraday is 96500 coulombs. It is also one mole of electrons.
If current of 0.2 Apms is passed through copper(ll) sulphate for tow hours, how much copper do you get?
Q= IT
If current of 0.2 Apms is passed through copper(ll) sulphate for tow hours, how much copper do you get?
- Write out the half equation
- Work out coulombs of electrons flowing
Q= IT
time is 2x60x60 (times 60 makes minutes, times 60 again makes it seconds)
Q= 0.2 x 7200= 1440 coulombs
- Convert C into moles of electrons
Mol= 1440/96500
Mol= 0.015
- Work out scale factor
For every 2 moles of electrons, there will be one Cu
Sf= Moles of product/ moles of electrons
Sf= 1/2
Sf= a half
- Work out moles of product using Scale factor
0.015x1/2= 0.0075 Moles of Cu
- Convert moles into mass
0.0075 x 63.5= 0.48g of copper
Sunday, 28 April 2013
1.55 write ionic half-equations representing the reactions at the electrodes during electrolysis
At the positive electrode, electrons will be lost: to show this we write the lost electrons as products:
2Br- > Br2 + 2e-
Make sure the charges are equal on both sides: 1- > 1-.
At the negative electrode, electrons will be gained so we write them as reactants:
2H+ + 2e- > H2
And to make sure the charges are the same on both sides: 0 > 0.
2Br- > Br2 + 2e-
Make sure the charges are equal on both sides: 1- > 1-.
At the negative electrode, electrons will be gained so we write them as reactants:
2H+ + 2e- > H2
And to make sure the charges are the same on both sides: 0 > 0.
1.54 describe experiments to investigate electrolysis, using inert electrodes, of aqueous solutions such as sodium chloride, copper(II) sulfate and dilute sulfuric acid and predict the products
Place inert electrodes (ones that wont react) into an aqueous solution.
At the positive electrode the negatively charged ion from the compound will form an atom. At the negative electrode the atom of the positive ion will form.
sodium chloride: Hydrogen at the negative; chlorine at the positive
copper(II) sulfate: copper at the negative; oxygen at the positive
dilute sulfuric acid: Hydrogen at the negative; oxygen at the positive
If the metal in the solution is more reactive then hydrogen, the hydrogen from the water will be a product, as the metal will bond with the oxygen.
Test the products using known methods: eg damp blue litmus paper turned red by chlorine.
At the positive electrode the negatively charged ion from the compound will form an atom. At the negative electrode the atom of the positive ion will form.
sodium chloride: Hydrogen at the negative; chlorine at the positive
copper(II) sulfate: copper at the negative; oxygen at the positive
dilute sulfuric acid: Hydrogen at the negative; oxygen at the positive
If the metal in the solution is more reactive then hydrogen, the hydrogen from the water will be a product, as the metal will bond with the oxygen.
Test the products using known methods: eg damp blue litmus paper turned red by chlorine.
1.53 describe experiments to investigate electrolysis, using inert electrodes, of molten salts such as lead(II) bromide and predict the products
Inert electrodes are ones that don't react with any other substances, but only play a role in the transfer of electrons.
To describe an experiment you need to be able to draw and label an electrolysis experiment. As an example:
To describe an experiment you need to be able to draw and label an electrolysis experiment. As an example:
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| figurepool.com |
Lead bromide will make lead and bromine, you can use chemical tests to see is you got these products from electrolysis.
1.52 understand that electrolysis involves the formation of new substances when ionic compounds conduct electricity
In electrolysis ionic compounds conduct electricity. Positively charged ions move to one end, negatively to the other, these are then turned into atoms (by losing their charge) and so new substances are formed.
1.51 describe experiments to distinguish between electrolytes and nonelectrolytes
Set up an electric circuit with an LED and a break in the wire, put both ends of wire into a solution/molten substance. If the LED lights up then there is a current flowing, this will only be able to happen if the solution is conducting: so it must be an electrolyte. Conversely if the LED does not light up then there is no current flowing, and so the solution has not conducted electricity meaning it must be a nonelectrolyte.
1.50 understand why ionic compounds conduct electricity only when molten or in solution
When ionic compounds are molten or in solution, the positive and negative ions separate this means that there are ions free to flow, and so they can conduct electricity.
1.49 understand why covalent compounds do not conduct electricity
In covalent compounds there are no electrons free to move, this means there can be no transfer of electricity through a covalent compound
1.48 understand that an electric current is a flow of electrons or ions
An electric current is a flow of electrons, although it can also be a flow of ions (as they have a charge.)
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